2x^2-3x-(k+1)=0

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Solution for 2x^2-3x-(k+1)=0 equation:


Simplifying
2x2 + -3x + -1(k + 1) = 0

Reorder the terms:
2x2 + -3x + -1(1 + k) = 0
2x2 + -3x + (1 * -1 + k * -1) = 0
2x2 + -3x + (-1 + -1k) = 0

Reorder the terms:
-1 + -1k + -3x + 2x2 = 0

Solving
-1 + -1k + -3x + 2x2 = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + -1k + -3x + 1 + 2x2 = 0 + 1

Reorder the terms:
-1 + 1 + -1k + -3x + 2x2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1k + -3x + 2x2 = 0 + 1
-1k + -3x + 2x2 = 0 + 1

Combine like terms: 0 + 1 = 1
-1k + -3x + 2x2 = 1

Add '3x' to each side of the equation.
-1k + -3x + 3x + 2x2 = 1 + 3x

Combine like terms: -3x + 3x = 0
-1k + 0 + 2x2 = 1 + 3x
-1k + 2x2 = 1 + 3x

Add '-2x2' to each side of the equation.
-1k + 2x2 + -2x2 = 1 + 3x + -2x2

Combine like terms: 2x2 + -2x2 = 0
-1k + 0 = 1 + 3x + -2x2
-1k = 1 + 3x + -2x2

Divide each side by '-1'.
k = -1 + -3x + 2x2

Simplifying
k = -1 + -3x + 2x2

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